Puzzled ! Math Minded

[77SceptreOB]

Originally Posted by abl1111

Does my calculation make sense ?

Add 2 gallons of fresh gas to a 1/2 gallon of the heavily concentrated/oiled gas to get me pretty darn close ? Gets you to about 2.56 (50:1 is 2.6)

How do you come by your answers ?

I did:

2.5 gal : 32oz of oil is equal to 1 gallon of gas : 12.8 oz of oil

My theory -- If I added (4) gallons of clean gas to the (1) gallon with 12.8 - for a total of (5) gallons ( less the 12.8 oz which I didn't worry about ), then it would be about 2.56 of oil for the (5) gallons overall. Sound about right ?

Yes, I agree with you and your calcs.

I thought you were asking in your original post how to make ONE gallon with the proper ratio (50:1) utilizing the oil rich gas mixture you already had in your container.

We need to have Denny (Bushwacker) chime in on this one...LOL!

[NoBones]

Holy Moly....

Use what you have in your weed whacker, blower, chain saw or what ever..

All else fails just dump it !! Start over...

[Bushwacker]

Originally Posted by 77SceptreOB

Yes, I agree with you and your calcs.

I thought you were asking in your original post how to make ONE gallon with the proper ratio (50:1) utilizing the oil rich gas mixture you already had in your container.

We need to have Denny (Bushwacker) chime in on this one...LOL!

Water Rat is right if you want to convert the whole mix to 50:1 . . . just add 10 gallons of straight gas and you'll have a 50:1 mix! But Jim is right if you want just 1 gal of 50:1 mix. But Ken has the most practical answer . . . many of the air cooled lawn tools run much hotter than outboards, so running only 1 gallon of a richer oil mixture in them really is no big deal! But the most important factor is NOT to use E-10 gas in lawn equipment, as it will dissolve their cheap Chinese fuel lines! I learned a long time ago from local lawnmower shop to only run real non-ethanol gas in those things!